Welcome toVigges Developer Community-Open, Learning,Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
713 views
in Technique[技术] by (71.8m points)

language agnostic - How do you know when to use fold-left and when to use fold-right?

I'm aware that fold-left produces left-leaning trees and fold-right produces right-leaning trees, but when I reach for a fold, I sometimes find myself getting bogged down in headache-inducing thought trying to determine which kind of fold is appropriate. I usually end up unwinding the entire problem and stepping through the implementation of the fold function as it applies to my problem.

So what I want to know is:

  • What are some rules of thumb for determining whether to fold left or fold right?
  • How can I quickly decide which type of fold to use given the problem I'm facing?

There is an example in Scala by Example (PDF) of using a fold to write a function called flatten which concatenates a list of element lists into a single list. In that case, a right fold is the proper choice (given the way the lists are concatenated), but I had to think about it a bit to arrive at that conclusion.

Since folding is such a common action in (functional) programming, I'd like to be able to make these kinds of decisions quickly and confidently. So... any tips?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

You can transfer a fold into an infix operator notation (writing in between):

This example fold using the accumulator function x

fold x [A, B, C, D]

thus equals

A x B x C x D

Now you just have to reason about the associativity of your operator (by putting parentheses!).

If you have a left-associative operator, you'll set the parentheses like this

((A x B) x C) x D

Here, you use a left fold. Example (haskell-style pseudocode)

foldl (-) [1, 2, 3] == (1 - 2) - 3 == 1 - 2 - 3 // - is left-associative

If your operator is right-associative (right fold), the parentheses would be set like this:

A x (B x (C x D))

Example: Cons-Operator

foldr (:) [] [1, 2, 3] == 1 : (2 : (3 : [])) == 1 : 2 : 3 : [] == [1, 2, 3]

In general, arithmetic operators (most operators) are left-associative, so foldl is more widespread. But in the other cases, infix notation + parentheses is quite useful.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to Vigges Developer Community for programmer and developer-Open, Learning and Share
...